program to find operators by using pointer

114./*Write a program to find operators by using pointer*/

#include<stdio.h>

#include<conio.h>

void main()

{

            int x,a,y,b,*ptr1,*ptr2,c,d;

            clrscr();

            printf("\nENTER AN INTEGER:");

            scanf("%d",&x);

            fflush(stdin);

            printf("\nENTER AN INTERGER:");

            scanf("%d",&y);

            ptr1=&x;

            ptr2=&y;

            a=*ptr1-*ptr2;

            b=*ptr1* *ptr2+8;

            printf("\na=%d\nb=%d",a,b);

            printf("\nx-y or *ptr1-*ptr2=%d",a);

            printf("\nx*y+8 Or *ptr1* *ptr2+8=%d",b);

            printf("\nAddress of x=%u",ptr1);

            printf("\nAddress of y=%u",ptr2);

            c= 5-*ptr2 / *ptr1-2;

            printf("\nc=%d",c);

            *ptr1=*ptr2-5;

            printf("\nx=%d",*ptr1);

            d=*ptr1* *ptr2 *6;

            printf("\nc=%d",d);

            getch();

}

OUTPUT

            ENTER AN INTEGER : 6

ENTER AN INTEGER : 3

a =3

b = 26

x-y Or *ptr1 – “ptr2=3

x*y + 8 Or *ptr1 * *ptr2 + 8 = 26

Address of x = 65524

Address of y= 65520

C = 3

X = -2

C = -36